The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:
A. 5 : 2
B. 7 : 3
C. 9 : 2
D. 13 : 4
Answer: Option B
Solution (By Examveda Team)
Let the ages of father and son 10 years ago be 3x and x years respectively.Then, (3x + 10) + 10 = 2[(x + 10) + 10]
⇒ 3x + 20 = 2x + 40
⇒ x = 20
∴ Required ratio
= (3x + 10) : (x + 10)
= 70 : 30
= 7 : 3
This Question Belongs to Arithmetic Ability >> Problems On Ages
10 year before
f age 30
s age 10
f is thrice older than s
after 10 year
f 40
s 20
f is twice older than s
40:20
2:1
how ten was added twice