The total length of a cranked bar through a distance (d) at 45° in case of a beam of effective length L, is
A. L + 0.42 d
B. L + (2 × 0.42 d)
C. L - (0.42 d)
D. L - (2 × 0.4 d)
Answer: Option B
A. L + 0.42 d
B. L + (2 × 0.42 d)
C. L - (0.42 d)
D. L - (2 × 0.4 d)
Answer: Option B
A. Mid-section formula
B. Trapezoidal formula
C. Prismoidal formula
D. All the above
Size, capacity and materials need be specified for
A. Bib-cocks
B. Stop-cocks
C. Ball valves
D. All the above
The expected out turn of 12 mm plastering with cement mortar is
A. 2.5 sq m
B. 4.0 sq m
C. 6.0 sq m
D. 8.0 sq m
A. Excavation
B. Surface dressing
C. Cutting
D. Surface excavation
For a 45° cranked bar in a beam, the extra length due to the crank is calculated from the inclined portion.
For a crank over a vertical distance
Inclined length=d/sin45°
=1.414d
The corresponding horizontal projection is:
dcot45°=d
Hence, extra length for one crank:
2(1.414d-d)=0.828d
Therefore, for a beam of effective length (L):
Length of cranked bar=L+0.828d
How